circumference of r=23cm
1. circumference of r=23cm
Answer:
C≈144.51
Step-by-step explanation:
C=2πr=2·π·23≈144.51326
Answer:
144.44 cmStep-by-step explanation:
[tex]formula = \: r \times 2 \times pi\pi(3.14)[/tex]
[tex] =23cm \times 2 \times 3.14[/tex]
[tex] = 46cm \times 3.14[/tex]
[tex] = 144.44cm[/tex]
hope it helps~✨
2. what is Formula 23cm
Answer:
9.055Step-by-step explanation:
Yan po!!#JATDOG!!3. 1. cube with s= 23cm
Answer:
the answer is 3 cause 3×3×3=27.
4. b=17cm and c=23cm l, find BC
Answer:
391
Step-by-step explanation:
BxC = 17cm x 23cm
[tex]17 \times 23 = 391[/tex]
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5. Instruction: Solve the perimeter of the given polygon.1.) What is the perimeter of an octagon if it has a measurement of 15cm? Example answer: 23cm 2.) What is the perimeter of a heptagon if it has a measurement of 9mm? Example answer: 23cm or 23 cm 3.) What is the perimeter of a nonagon if it has a measurement of 17m? Example answer: 23cm or 23 cm 4.) What is the perimeter of a pentagon if it has a measurement of 35cm? Example answer: 23cm or 23 cm 5.) What is the perimeter of a triangle if it has a measurement of 27cm? Example answer: 23cm or 23 cm 6.) What is the perimeter of a quadrilateral if it has a measurement of 128mm? Example answer: 23cm or 23 cm 7.) What is the perimeter of a hexagon if it has a measurement of 38m? Example answer: 23cm or 23 cm 8.) What is the perimeter of a dodecagon if it has a measurement of 100m? Example answer: 23cm or 23 cm 9.) What is the perimeter of a hendecagon if it has a measurement of 35cm? Example answer: 23cm or 23 cm 10.) What is the perimeter of a decagon if it has a measurement of 20mm? Example answer: 23cm or 23 cm josemarionecody
Answer:
120cm63mm153m175cm81cm512mm228m1200m385cm200mmStep-by-step explanation:
Perimeter of an octagon with a measurement of 15cm:
Perimeter = 15cm x 8 = 120cm
Perimeter of a heptagon with a measurement of 9mm:
Perimeter = 9mm x 7 = 63mm
Perimeter of a nonagon with a measurement of 17m:
Perimeter = 17m x 9 = 153m
Perimeter of a pentagon with a measurement of 35cm:
Perimeter = 35cm x 5 = 175cm
Perimeter of a triangle with a measurement of 27cm:
Perimeter = 27cm x 3 = 81cm
Perimeter of a quadrilateral with a measurement of 128mm:
Perimeter = 128mm x 4 = 512mm
Perimeter of a hexagon with a measurement of 38m:
Perimeter = 38m x 6 = 228m
Perimeter of a dodecagon with a measurement of 100m:
Perimeter = 100m x 12 = 1200m
Perimeter of a hendecagon with a measurement of 35cm:
Perimeter = 35cm x 11 = 385cm
Perimeter of a decagon with a measurement of 20mm:
Perimeter = 20mm x 10 = 200mm
6. d = 14cm, h= 23cm Formula: SA =2πr2 + 2πrh
Answer:c. 1, 318.8cm2
Hope it helps:
7. find the area of circle Given. A-? r-23cm
PROBLEM :
find the area of circle. R - 23cmFORMULA :
[tex]\text{A = \: πr²} [/tex]SOLUTION :
♦ To find the area of a circle multiply the radius two times in itself then, multiply the answer in [tex]\text\green{\underline{pi \: ( \: π \: = 3.14 \: )\: }}[/tex]
[tex] \small\begin{array}{|c|}\hline \\ \text{A \: = \: πr²} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \text{A \: = \: 3.14 ( 23 cm )² } \: \\ \text{A = \: 3.14 ( 529 cm² )} \: \\ \\ \: \: \: \: \: \: \: \: \boxed{ \text \green{A \: = 1,661.06 cm²} } \: \: \: \: \: \: \: \\ \\ \hline \end{array}[/tex]
ANSWER :
[tex]\because [/tex] The area of a circle is 1,661.06 cm²
===========================================
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8. The red triangle is equilateral with a side of 23cm. find the perimeter.
Answer:
In geometry, an equilateral triangle is a triangle in which all three sides have the same length.
P = 3a = 3 · 23 = 69
9. what is the area of 16cm and 23cm 9cm
[tex]\huge {\red {\underline { \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }}} [/tex]
A = Lwh
A = 16cm × 23cm × 9cm
A = 368 × 9cm
A = 3,312 cm²
[tex]\huge {\red {\underline { \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }}} [/tex]
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10. Activity 4 : if b=17 cm and c=23cm find a
Answer:
It is best to assume that this is a triangle problem and this constitutes the Pythagorean theorem.
[tex]c^{2} =a^{2} +b^{2}[/tex]
Identifying the given:
b = 17
c = 23
a = ?
Substituting the given to the formula we get;
[tex]23^{2} =a^{2} +17^{2}[/tex]
[tex]529=a^{2} +289[/tex]
By transposition, combine like terms to get a single term on both sides we get,
[tex]529-289=a^{2}[/tex]
[tex]240=a^{2}[/tex]
Getting the square root of both sides;
[tex]a=\sqrt{240}[/tex]
a= 15.5 cm
For more information, visit the link below.
https://brainly.ph/question/2113315
11. what is the perimeter of triangle when the given is 30cm, 23cm,26cm
to get the perimeter, you just have to add all the sides, so 30+23+26= 69the sides 30cm, 23cm, 26cm,
just add 30cm+23cm+26cm= 79cm
12. show the area of the rectangle having a h=18cm and w=23cm
Answer:
414
Explanation:
just multiply the length(height) by width
13. what is the peremiter of triangle whose side measure 23cm 15cm and 19cm
the formula in finding the perimeter of a triangle is equal to side+side+side.
so 23+15+19
38+19
57square centimeter
14. diameter1)57cm2)23cm3)36in
Answer:
ano po yan
Step-by-step explanation:
Meron po bang picture yan?
15. a piece of paper measure 23cm by 30cm. what is it's area in cm2?
AREAPROBLEM
A piece of paper measure 23cm by 30cm. What is it's area in cm²?
ANSWERThe area of the given piece of paper is 690 cm².
SOLUTIONWe know that a piece of paper is a rectangular shape. Thus, we will use the formula for the area of a rectangle which is A = L × W.
Since the given measurements are in its eight unit already, we can just substitute it to the formula.
A = L × W
A = 23 cm × 30 cm
A = 690 cm²
Therefore, the area of the given piece of paper is 690 cm².
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Answer:
Given :-Length = 30 cm
Breadth = 23 cm
To Find :-Area
Solution :-We know that,
Area = Length × Width
Area = 30 × 23
Area = 690 cm²
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16. what is the volume of a 21cm×23cm×25cm rectangular box?
Answer:12075cm or 120.75mHow do we even get 12075 CM or 120.75 m?:We get it by multiplying its Height, Width, and LengthThe multiplying:21cm x 23cm is 483cm or 4.83m483cm x 25cm is 12075cm or 120.75
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17. What is the circumference of the radius of 23cm
Answer:
144.51cm^2Step-by-step explanation:
2 x π x 23 = 144.51cm^2
Answer:[tex]\Large\boxed{\sf{144.51~cm^2}}[/tex]
Solution:To find the circumference I will use the formula C = 2πr.
where -
C = circumferenceπ = pir = radiusplug the values in:
C = 2 * pi * 23C = 46 * piC = 144.51 cmTherefore, the circumference is 144.51 cm.
18. Find the perimeter of the rectangle whose length is 12cm and breadth is 23cm.
[tex]\large\underline{\mathbb{\blue{ \: \: \: PERIMETER \: \: \: }}}:[/tex]
[tex]=======================[/tex]
[tex]\begin{gathered}\begin{gathered}{\underline{\huge \mathbb{A} {\large \mathrm {NSWER : }}}} \\\end{gathered} \end{gathered} [/tex]
[tex]\begin{gathered} \large\qquad \quad\sf Perimeter{\small_{(rectangle)}} = \underline{ \bold{\green{ \pmb{ \: \: \: 70cm \: \: \: }}}} \\ \end{gathered} [/tex]
[tex]=======================[/tex]
[tex]\begin{gathered}{\underline{\huge \mathbb{S} {\large \mathrm {OLUTION : }}}} \\ \end{gathered} [/tex]
Given that,
[tex]\begin{gathered} \sf{Length = \underline\red{ \: \: 12cm \: \: }} \\ \end{gathered} [/tex][tex]\begin{gathered} \sf{Breadth = \underline{ \blue{ \: \: 23cm \: \: }}} \\ \end{gathered}[/tex]To find:
What is the perimeter?We know,
[tex]\begin{gathered}\quad \bold{ \hookrightarrow \: Perimeter \small_{(Rectangle)} = \underline{{\boxed{\bold{ \: \: \: 2(\red{length} + \blue{breadth}) \: \: \: }}}}} \\ \end{gathered} [/tex]
[tex]\begin{gathered} \underline{ \mathcal{ \blue{ \: \: \: Diagram \: \: \: }}} : \\ \end{gathered} [/tex]
[tex]\begin{gathered} \qquad\begin{gathered}\sf{ \blue{23\: cm }\:}\huge\boxed{ \begin{array}{cc} \: \: \: \: \qquad\\ \end{array}} \\ \: \: \: \: \: \sf{ \red{12 \: c m}}\end{gathered}\end{gathered} [/tex]
So,
[tex]\begin{gathered}\sf \implies \: Perimeter \small_{(Rectangle)} = 2( \red{length} + \blue{breadth}) \\ \end{gathered} [/tex]
[tex]\begin{gathered}\sf \implies \: Perimeter{\small_{(rectangle)}} = 2( \red{12cm} + \blue{ 23cm}) \\ \end{gathered}[/tex]
[tex]\begin{gathered} \sf \implies \: Perimeter{\small_{(rectangle)}} = 2( \pink{35cm}) \\ \end{gathered}[/tex]
[tex]\begin{gathered} \sf \implies \: Perimeter{\small_{(rectangle)}} = \underline{\bold{\green{ \pmb{ \: \: \: 70cm \: \: \: }}}} \\ \end{gathered} [/tex]
[tex]=======================[/tex]
[tex]\large\sf{\pmb{{\# CarryOnLearning \qquad \quad- \sf\copyright \: \large\tt{Eutoxia}}}}[/tex]
19. what is the areaof a parallelogram with a length of 62cm and width of 23cm
Formula for parallelogram: Base(B) × Height(H) or Length(L) × Width(W)
Solution:
L × W
62 × 23
= 1426 cm²
ANSWER: The area of the parallelogram is 1426 cm².20. a sphere has a radius of 23cm what is its surface area
Answer:
formula: A=4πr^2. where r=23cm
A=4π(23)^2
=2116π
21. what is the volume of a 21cm × 23cm × 25cm rectangular box?
Answer:
Answer:
im sryy
Explanation:
i need more points for me to ask a question
Step-by-step explanation:
Answer:
im sryy
Explanation:
i need more points for me to ask a questionAnswer:
im sryy
Explanation:
i need more points for me to ask a questionAnswer:
im sryy
Explanation:
i need more points for me to ask a questionAnswer:
im sryy
Explanation:
i need more points for me to ask a question
Answer:
12,075 cm
Step-by-step explanation:
multiply all the numbers and you'll get the answer
22. Find the surface area of this wooden box 20 cm, 20cm and 23cm
Answer:
The surface area of the wooden box is 2640 cm².Step-by-step explanation:
Given :The surface area of the cuboidal wooden box is 20 cm, 20 cm, and 23 cm.To Find :Total surface area of the wooden box.Solution :By using the formula of Total surface area of cuboid, we will find the Total surface area of the wooden box. Here, l = 20 cm, b = 20 cm, h = 23 cm.
According to the question :
[tex] \sf \longrightarrow {TSA\ =\ 2(lb\ +\ bh\ +\ hl)} [/tex]
[tex] \sf \longrightarrow {TSA\ =\ 2(20 \times 20\ +\ 20 \times 23\ +\ 23 \times 20)} [/tex]
[tex] \sf \longrightarrow {TSA\ =\ 2(400\ +\ 460\ +\ 460)} [/tex]
[tex] \sf \longrightarrow {TSA\ =\ 2 \times 1320} [/tex]
[tex] \sf \longrightarrow {\underline{TSA\ =\ 2640\ cm^2}} \bigstar [/tex]
∴ Hence, the required surface area of the wooden box is 2640 cm².
23. what is the value s= equel 23cm
[tex] \huge{brainliest \: me \: }{} [/tex]
24. What is the perimeter of 78cm and 23cm?
Answer:
Therefore the perimeter of 78cm will be [tex]\sf\color{green}\tt{72cm}[/tex]
[tex] \\ [/tex]
Therefore the perimeter of 23cm will be [tex]\sf\color{green}\tt{84cm}[/tex]
#CarryOnLearning25. find the area of this irregular polygon 24cm 23cm 15cm
Answer:
The area is 8280cm2
Step-by-step explanation:
To find area multiply length by width by height.
26. L = 23cm, W = 10cm H = 3cm
[tex]{\huge{\boxed{\mathcal{{Answer\:}}}}}[/tex]
690Explanation:
L×W×H
23×10×3=690
HOPE ITS HELP
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27. find the area of circle Given. A-? r-23cm
AREA
Formula: [tex]\tt{{A\:=\:πr²}}[/tex]
[tex]\huge{\overline{\quad\quad\quad\quad\quad\quad\quad\quad \ \ \ }}[/tex]
[tex]\large\tt\bold{{Problem:}}[/tex] Find the area of a circle. R - 23 cm
[tex]\large\tt\bold{{Solution:}}[/tex]
- To find the area of a circle multiply the radius two times in itself then, multiply the answer in [tex]\tt\underline{{Pi\:(\:π\:=\:3.14\:).}}[/tex]
[tex]\tt{{A\:=\:πr²}}[/tex][tex]\tt{{A\:=\:3.14\:(\:23\:cm\:)²}}[/tex][tex]\tt{{A\:=\:3.14\:(\:529\:cm²\:)}}[/tex][tex]\tt{{A\:=\:}}[/tex][tex]\tt\green{{1,661.06\:cm²}}[/tex]Therefore, the area of a circle is 1,661.06 cm².
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28. Solve the right triangle a = 23cm and b = 32cm
Answer:
[tex]\sqrt{ 55}[/tex]
Step-by-step explanation:
Answer:
√ 1553
Step-by-step explanation:
c^2 = a^2 + b^2
c^2 = 32^2 + 23^2
c^2 = 1024 + 529
c^2 = 1553
√ c^2 = √ 1553
c = √ 1553 or 39.4 or 39
29. if b = 17 cm , C = 23cm find: a, A, B
Answer:
C = 23 cm
B = 17 cm
A. 15.5 cm
30. 5cm 8cm 10cm 16cm 23cm
Answer:
ano po ang instruction ng gagawin?
Answer:
pag aralaan moyan wagdito
Step-by-step explanation:
I don't know
